Math, asked by anonymuos123, 4 months ago

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Answered by Tubamir
1

Answer:

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Step-by-step explanation:

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Answered by Anonymous
3

Answer:

1- x2+x-12=0

standard form :-x2+x-12=0

comparing with ax2+bx+c=0 we get,

a=1 b=1 c= -12

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2- x2+6x+8=0

standard form:- x2+6x+8=0

comparing with ax2+bx+c=0 we get,

a=1 b=6 c=8

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3- x2-8x+15=0

standard form:-x2-8x+15=0

comparing with ax2+bx+c=0 we get,

a=1 b= -8 c=15

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4-(3x+2)(4x-1)

standform form:-12x2+5x-2=0

comparing with ax2+bx+c=0 we get,

a=12 b=5 c= -2

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5-2x2-(x+2)(x-3)=11

standform form:-x2+5x-17=0

comparing with ax2+bx+c=0 we get,

a=1 b=5x c= -17

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hope it help you

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