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Answer 1

Step-by-step explanation:2x−y−4=0 …(i)

2x−y−4=0 …(i)y=2x−4

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.It is clear from the graph that the two lines intersect at (1,−2).

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.It is clear from the graph that the two lines intersect at (1,−2).So the solution of the given equations are x=1 and y=−2.

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.It is clear from the graph that the two lines intersect at (1,−2).So the solution of the given equations are x=1 and y=−2.The area of the triangle formed by these lines and Y axis =1/2 ×base×height

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.It is clear from the graph that the two lines intersect at (1,−2).So the solution of the given equations are x=1 and y=−2.The area of the triangle formed by these lines and Y axis =1/2 ×base×height=1/2×3×1

2x−y−4=0 …(i)y=2x−4When x=1,y=2×1−4=2−4=−2When x=2,y=2×2−4=4−4=0When x=3,y=2×3−4=6−4=2x= 1 ,2 ,3y= −2 ,0 ,2Mark the above points on graph. Join them.x+y+1=0 …(ii)y=−x−1When x=0,y=0−1=−1When x=−2,y=2−1=1When x=−1,y=1−1=0x= −2 ,−1 ,0y= 1 ,0 ,−1Mark the above points on graph. Join them.It is clear from the graph that the two lines intersect at (1,−2).So the solution of the given equations are x=1 and y=−2.The area of the triangle formed by these lines and Y axis =1/2 ×base×height=1/2×3×1=1.5sq. units

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