Question

help fastt ???? !!!!!!​

Answer 1

Answer:-

The change in P.E (Δ U) is 15 J

Given:-

Mass of stone (M) = 500 g = 0.5 Kg

Initial height (h₁) = 2 m

Final height (h₂) = 5 m

Explanation:-

$\rule{300}{1.5}$

We Know,

$\bigstar\;\underline{\boxed{\sf \Delta U=U_{f}-U_{i}}}$

Here,

ΔU Denotes Change in P.E

U_{f} Denotes Final P.E

U_{i} Denotes Initial P.E

Substituting the values,

$\longrightarrow\sf \Delta U=\bigg(Mg\;h_{2}\bigg)-\bigg(Mg\;h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U =Mg\times \bigg(h_{2}-h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U = 0.5\times 10\bigg(5-2\bigg)\\\\\\\longrightarrow\sf \Delta U =5\times 3\\\\\\\longrightarrow\sf \Delta U = 15\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf \Delta U = 15\;J}}}}$

∴ The change in P.E (Δ U) is 15 J.

$\rule{300}{1.5}$

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \sf \blue{Given :-}$

Mass of stone (M) = 500 g = 0.5 Kg

Initial height (h₁) = 2 m

Final height (h₂) = 5 m

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$\: \: \: \: \: \: \: \: \: \: \: \: \: \sf \blue{Substituting \: the \: values}$

$\longrightarrow\sf \Delta U=\bigg(Mg\;h_{2}\bigg)-\bigg(Mg\;h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U =Mg\times \bigg(h_{2}-h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U = 0.5\times 10\bigg(5-2\bigg)\\\\\\\longrightarrow\sf \Delta U =5\times 3\\\\\\\longrightarrow\sf \Delta U = 15\\\\\\\longrightarrow \large{\underline{\boxed{\purple{\sf \Delta U = 15\;J}}}}$

$\sf \pink{∴ The \: change \: in \: P.E \: (Δ U) \: is \: 15 J} \large \: \green{✓}$

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