Question

help for find this answer​

Answer 1

Answer:

case 1.

let x = 0

then,

0^2 + 4×0+5

0+0+5

=5

case 2

let x = 1

then

1^2+4×1+5

1+4+5

=10

case 3

let x = 2

then

2^2+4×2+5

4+8+5

=17

Answer 2

Answer will be 5,10&17

Step-by-step explanation:

$p(x) = x ^{2} + 4x + 5 \\ p(0) = 0 ^{2} + 4 \times 0 + 5 = 5 \\ p(1) = 1 {}^{2} + 4 \times 1 + 5 = 10 \\ p(2) = 2 {}^{2} + 4 \times 2 + 5 = 17$

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