Math, asked by aen, 1 year ago

help for question 4,5,6

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Answered by snehitha2
0
(4)

(343-⅔)^3/2

→ (343(3) -⅔)^3/2

→ [(1029-2)/3]^3/2

→ (1027/3)^3/2

(5)

(⅓)^-3 × (⅓)^-1

a^m×aⁿ = a^m+n

→ (⅓)^-3+(-1)

→ (⅓)^-4

(1/a)^-n = aⁿ

→ 3⁴

→ 81

(6)

(a) 2³×2^-2

→ 2^3+(-2)

→ 2¹

→ 2

(b) 4^½ × 9^½

→(2²)^½ × (3²)^½

→2¹×3¹

→ 6

Hope it helps
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