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We have,f(x)= 2x+1 and g(x) = x2 - 2, ∀ ∈ R
∴ gof = g(f(x))
= g(2x+1)
= (2x+1)2-2
= 4x2 + 4x + 1 - 2
= 4x2 + 4x - 1
Please mark me the brainliest!
Suhani
xx
∴ gof = g(f(x))
= g(2x+1)
= (2x+1)2-2
= 4x2 + 4x + 1 - 2
= 4x2 + 4x - 1
Please mark me the brainliest!
Suhani
xx
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