Math, asked by asyaalmnsoori, 7 months ago

help guys !!!!!
14
3
4

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Answered by Anonymous
3

Answer:

\rm a_{23} = 4

Step-by-step explanation:

\rm A = \left[\begin{array}{ccc}\rm a_{11}&\rm a_{12}&\rm a_{13}\\\rm a_{21}&\rm a_{22}&\rm a_{23}\\\rm a_{31}&\rm a_{32}&\rm a_{33}\end{array}\right]

We know that we can represent a matrix A as \rm [a_{ij}]_{m \times n}, where i is the number of the row like 1st row, and j is the number of the column, like 1st column

m is the total number of rows and n is the total number of columns

So the above matrix A we can represent as \rm [a_{ij}]_{3 \times 3}

In the question we have to find the element which is presnt at the intersection of 2nd row and 3rd column

Given matrix is,

\rm A = \left[\begin{array}{cccc}1&2&3&4\\12&3&4&1\\13&14&1&2\end{array}\right]

If we write the above matrix in the form of \rm [a_{ij}]_{m \times n}

We can write the above matrix A as,

\rm A =  \left[\begin{array}{cccc}\rm a_{11}&\rm a_{12}&\rm a_{13}&\rm a_{14}\\\rm a_{21}&\rm a_{22}&\rm a_{23}&\rm a_{24}\\\rm a_{31}&\rm a_{32}&\rm a_{33}&\rm a_{34}\end{array}\right]

If we compare both the matrices then we get to know that the element \rm a_{23} = 4

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