Question

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Answer 1

Answer:

Let the three consecutive numbers are

x-1, x, x+1.

according to question,

(x-1) + (x) + (x+1)

= 51or, 3x

= 51 or,

x= 17therefore numbers are 16, 17, 18And middle one is 17.

Step-by-step explanation:

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Answer 2

Answer:

Here is the answer

Step-by-step explanation:

Let the consecutive integers be a-2,a and a+2

So a-2+a+a+2=51 (Given)

3a=51

a=51/3

a=17

So a-2=15,a=17 and a+2=19.

Verification :-

a-2+a+a+2=51

15+17+19=51

51=51

LHS=RHS

Hence verified.

So the three consecutive integers whose sum is 51 are 15,17 and 19.The middle one is 17.

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