Question

help guys
it's matrix​

Answer 1

Answer:

$B=\left[\begin{array}{ccc}7&3\\6&4\end{array}\right]$

Step-by-step explanation:

$A = \left[\begin{array}{ccc}4&1\\2&3\end{array}\right] \\A^2= A+2B$

$A^2 = \left[\begin{array}{ccc}4&1\\2&3\end{array}\right] \left[\begin{array}{ccc}4&1\\2&3\end{array}\right]=\left[\begin{array}{ccc}4X4+2X1&4X1+1X3\\2X4+3X2&2X1+3X3\end{array}\right] =\left[\begin{array}{ccc}18&7\\14&11\end{array}\right]$

$LET \frac{}{} B= \left[\begin{array}{ccc}w&x\\y&z\end{array}\right]$

$A = \left[\begin{array}{ccc}4&1\\2&3\end{array}\right] \\\\A^2= A+2B=\left[\begin{array}{ccc}4&1\\2&3\end{array}\right] + 2\left[\begin{array}{ccc}w&x\\y&z\end{array}\right] =\left[\begin{array}{ccc}4+2w&1+2x\\2+2y&3+2z\end{array}\right]$

$=>\left[\begin{array}{ccc}18&7\\14&11\end{array}\right]=\left[\begin{array}{ccc}4+2w&1+2x\\2+2y&3+2z\end{array}\right]$

$4 + 2w = 18 => w = 7\\1 + 2x = 7 => x = 3\\2 + 2y = 14 => y = 6\\3 + 2z = 11 => z =4$

$B= \left[\begin{array}{ccc}w&x\\y&z\end{array}\right]=\left[\begin{array}{ccc}7&3\\6&4\end{array}\right]$

Answer 2

nope this is matrix.......