Question

help guys Solve: 1. A solution contains 30g of common salt in 240g of water. Calculate the concentration in terms of mass by mass percentage of the solution. 2.Calulate the mass of the sodium sulphate required to prepare its 30% (mass percent)solution in 200 grams of water. 3.Teacher asked students to prepare a 20% solution (Mass/Mass) of sugar in water. Ramesh dissoved 20g of sugar in 100g of water while Sara prepared it by dissolving 20g of sugar in water to make 100g of the solution. a)Are two solutions of the same concentration? b)Compare the mass % of the two solutions.

Answer 1

Answer:

This is your answer...

Explanation:

1. Concentration of solution  = mass of solute / mass of solution

Mass of common salt is 30g .

Mass of water is 240g .

Mass of solution = 30 + 240 = 270g  

Concentration of solution =  (30 / 300) * 100

Concentration = 30%

2. Mass of the solution = mass of solute + mass of solvent

Given that the mass percent of sodium sulphate solution is 30%.

Let the mass of sodium sulphate which is required to prepare this solution be x grams.

Given that the mass of water is 200 g.

So,

30 = [x/(x + 100)] * 100

30/100 = [x/(x + 100)]

3/10 = [x/(x + 100)]

x = (3/10) x (x+100)

x = (3x + 300) / 10

3x + 300 = 10x

10x - 3x = 300

7x = 300

x = 42.8

Thus, 42.8 g of sodium sulphate is required.

3. a) No, both are different.

   b) According to the solution prepared by Ramesh,

Mass of sugar he took (Solute) = 20 g

Mass of water he took (Solvent) = 100 g

Thus Mass % of the solution = mass of solute / mass of solution

                                               = (20 / 120) * 100

                                               =  50 / 3

                                               = 16.66 %

According to the solution prepared by Sara,

Mass of sugar she took (Solute) = 20 g

Mass of Solution she took  = 100 g

Thus Mass % of the solution =  mass of solute / mass of solution

                                               = (20 / 100) * 100

                                               = 20 %

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Answer 2

1) Concentration in terms of mass by mass percentage of the solution = 30%

2) Mass percent of solution = 85.7g

3a) The two solutions are not of the same concentration.

3b) Mass percent of solution prepared by Ramesh is 16.66%

Mass percent of solution prepared by Sara is 20%

1. Concentration of solution = mass of solute + mass of solution

• Mass of common salt = 30g.
• Mass of water = 240g.
• Mass of solution = 30+ 240 = 270g

Concentration of solution =

$= \frac{mass \: of \: solute}{mass \: of \: solution} \times 100 \\ = \frac{30}{300} \times 100 \\ = \frac{3000}{300} \\ = 30\%$

Concentration in terms of mass by mass percentage of the solution = 30%

2) Mass of the solution = mass of solute + mass of solvent

• As we know, mass percent of sodium sulphate solution = 30%.
• Mass of water = 200g
• Let the mass of sodium sulphate which is required to prepare this solution be x grams.

As we know,

Mass percent of solution =

$= \frac{solute}{solution} \times 100 \\ 30 = \frac{x}{x + 200} \times 100 \\ 30x + 6000 = 100x \\ 70x = 6000 \\ x = \frac{6000}{70} \\ x = 85.7 \: \g$

Mass percent of solution = 85.7 g required

3)

a) The two solutions are not of the same concentration.

b) According to the solution prepared by Ramesh,

• Mass of sugar he took (Solute) = 20 g
• Mass of water he took (Solvent) = 100 g
• Thus Mass % of the solution = mass of solute mass of solution

$= \frac{20}{120} \times 100 \\ = \frac{2000}{120} \\ = 16.66\%$

Mass percent of solution prepared by Ramesh is 16.66%

According to the solution prepared by Sara,

• Mass of sugar she took (Solute) = 20 g
• Mass of Solution she took = 100 g
• Thus Mass % of the solution = mass of solute / mass of solution

$= \frac{20}{100} \times 100 \\ = \frac{2000}{100} \\ = 20\%$

Mass percent of solution prepared by Sara is 20%

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