Question

Help! Help! Hellpppp!! ​

Answer 1

Given:-

• 3x - y = 12

Solution:-

$\frac{ {8}^{x} }{ {2}^{y} } \\ \\ \\ \\ \\ = \frac{(2 {}^{ 3} ) {}^{x} }{ {2}^{y} } \\ \\ \\ \\ \\ = \frac{2 {}^{3x} }{2 {}^{y} } \\ \\ \\ \\ \\ = 2 {}^{3x - y} \\ \\ \\ \\ \\ = \boxed{ {2}^{12} }$

Hence, A option is correct.

Answer 2

Option A is the correct answer

${\orange{ \boxed{ \boxed{ \begin{array}{cc} \bf \to \: given \: : \\ \\ \rm \: 3x - y = 12 \: \: \: - - - (1) \\ \\ \sf \: we \: have \: to \:f ind \: the \: value \: of: \\ \\ \sf \hookrightarrow \: \rm \: \frac{ {8}^{x} }{ {2}^{y} } \\ \\ \red {\sf \: solution : } \\ \\ \rm \: \frac{ {8}^{x} }{ {2}^{y} } \\ \\ \rm = \frac{ {( {2}^{3} })^{x} }{ {2}^{y} } \\ \\ \rm = \frac{ {2}^{3x} }{ {2}^{y} } \\ \\ \rm = {2}^{3x - y} \\ \\ \rm = {2}^{12} \: \: \{ \: \sf \: from \: eqn.(1) \} \end{array}}}}}$

Friend, please again check my previous answer.

One more picture is added.