Question

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Answer 1

$\huge \pink{ \bigstar{ \underline{answer}}}$

Let the multiples be x+8, x+16 and x+24

$according \: to \: the \: problem$

$x + 8 + x + 16 + x + 24 = 888$

$3x + 48 = 888$

$3x = 888 - 48$

$3x = 840$

$x = \frac{840}{3}$

$x = 280$

$\huge\color{pink}{so}$

$x + 8 = 280 + 8 = 288$

$x + 16 = 280 + 16 = 296$

$x + 24 = > 280 + 24 = 304$

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Answer 2

Answer:

Let the multiples be x+8, x+16 and x+24

according \: to \: the \: problemaccordingtotheproblem

x + 8 + x + 16 + x + 24 = 888x+8+x+16+x+24=888

3x + 48 = 8883x+48=888

3x = 888 - 483x=888−48

3x = 8403x=840

x = \frac{840}{3}x=3840

x = 280x=280

\huge\color{pink}{so}so

x + 8 = 280 + 8 = 288x+8=280+8=288

x + 16 = 280 + 16 = 296x+16=280+16=296

x + 24 = > 280 + 24 = 304x+24=>280+24=304

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