Question

help help help help help​

Answer 1

Answer:

First one

Step-by-step explanation:

Value inside the root always has to be greater than or equal to 0

Answer 2

Answer:

f(x)=\sqrt{9-x^2}

9−x

2

Domain of the equation,

9-x^{2}x

2

≥0 [Since,for real numbers sq rt is always a positive number],

x^{2}x

2

-9≤0

(x+3)(x-3)=0

∴Domain⇒-3≤x≤3

f(x)=\sqrt{9-x^2}

9−x

2

is a semicircle having radius 3 and origin (0,0), [y=\sqrt{r^2-x^2}

r

2

−x

2

represents a semicircle,where r is the radius],

∵The range is the set of possible output values, which are shown on the y-axis.

And,since the maximum value of the semicircle on y-axis is 3 as the origin of the circle is (0,0) and radius is 3,

∴Range=[0,3]

⇒Pls refer the attachment of the graph given below,

Hope it helps you.