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A particle initially at rest moves with an acceleration 5m/s square for 5 seconds .Find the distance travelled in:
a. 4sec
b. 5sec​

Answer 1

Explanation:

In four sec,

5m/s square × 4

=20 m/s square.

In five sec,

5m/s square × 4

=25m/s square.

Please mark it as Brailiest.

Answer 2

Answer:

Here is your answer

(a)4sec.

initial velocity=0

acceleration=5m/s<2

distance travelled=4sec.

S1=ut+1/2at<2

S1=0×4+1/2×5(4)<2

S1=40m

(b)5sec.

initial=0

acceleration=5m/S<2

distance travelled=5sec.

S2=ut+1/2+at<2

S2=0×5+1/2×5×(5)<2

S2=62.5m

Ths is correct answer

this ques of class 9th

and gurukul school hari ke kalan

and u study in

thank u

i hope this will help u