Math, asked by omshiv7, 2 months ago

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Attachments:

Answers

Answered by Anonymous

145

Given :-

$\sf \dfrac{5x}{3}-\dfrac{x-1}{4}=\dfrac{x-3}{5}$

To find :-

Value of x

Solution :-

$\sf\red{ \: \: \: \: \: \: \: \: \: :\implies \dfrac{5x}{3}-\dfrac{x-1}{4}= \dfrac{x-3}{5}}\\$

$\: \: \: \: \: \: \: \: \: :\implies\sf \dfrac{(5x\times 4)- 3(x-1)}{12}= \dfrac{x-3}{5}\\$

$\: \: \: \: \: \: \: \: \: :\implies\sf \dfrac{20x-3x+3}{12}= \dfrac{x-3}{5}\\$

$\: \: \: \: \: \: \: \: \: :\implies \sf 5(17x+3)= 12(x-3)\\$

$\: \: \: \: \: \: \: \: \: :\implies\sf 85x+15= 12x-36\\$

$\sf \: \: \: \: \: \: \: \: \: :\implies\sf 85x-12x= -36-15\\$

$\: \: \: \: \: \: \: \: \: :\implies\sf 73x= -51\\$

$\red{\: \: \: \: \: \: \: \: \: :\implies\sf x=\dfrac{-51}{73}}\\$

Verification :-

First we have to solve the half equation then we will put the value of x.

$\sf\pink{ :\implies\dfrac{5x}{3}-\dfrac{x-1}{4}= \dfrac{x-3}{5}}\\ \\ :\implies\sf \dfrac{(5x\times 4)- 3(x-1)}{12}= \dfrac{x-3}{5}\\ \\ :\implies\sf \dfrac{20x-3x+3}{12}= \dfrac{x-3}{5}\\ \\ :\implies \sf 5(17x+3)= 12(x-3)\\ \\ \pink{:\implies\sf 85x+15= 12x-36}\\ \\ :\implies \sf \bigg(\dfrac{85\times -51}{73}+15\bigg)= \bigg(\dfrac{12\times -51}{73}-36\bigg)\\ \\ :\implies\sf \bigg(\dfrac{-4335+1095}{73}\bigg)= \bigg(\dfrac{-612-2628}{73}\bigg)\\ \\\pink{ :\implies\sf \bigg(\dfrac{-3240}{73}\bigg)= \bigg(\dfrac{-3240}{73}\bigg)}\\ \\ \sf \ \ L.H.S = R.H.S \ (Hence \ verified \ !) \\$

Answered by llCuteCandyll1

$\frac{5x}{3}-\frac{x-1}{4}= \frac{x-3}{5}$

$\frac{(5x\times 4)- 3(x-1)}{12}= \frac{x-3}{5}\\$

$\frac{20x-3x+3}{12}= \frac{x-3}{5}\\$

$5(17x+3)= 12(x-3)\\$

$85x+15= 12x-36\\$

$x=\frac{-51}{73}\\$

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