Physics, asked by sanskar6732, 9 months ago

HELP HELP HELP I NEED A HELPPPPPPPP !!!!

Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radii R and r such that their
periods are the same. Then the ratio between their centripetal acceleration is:

(A) R/r
(B) r/R
(C) R^2 / r^2
(D) r^2 / R^2​

Answers

Answered by Thakshayini
1

Answer:

hi there!!

Explanation:

happy helping ❤️

refer to the picture....as time is constant for both, I am using this formulae.

Attachments:
Answered by Ekaro
10

11th/Physics

Gravitation

Answer :

Two bodies of masses 10kg and 5kg are moving in concentric orbits of radii R and such that their periods are same.

We have to find the ratio between their centripetal acceleration.

⧪ First we have to derive relation between centripetal force acting on moving object in circular path and time period of revolution.

★ Centripetal force acting on the body of mass m moving with velocity v in circular path of radius r is given by

  • a = v² / r

We know that, v = r × ω = r × (2π/T)

ω denotes angular velocity

T denotes time period of revolution

➙ F = v² / r

➙ F = (2πr/T)² / r

➙ F = (4π²r²) / (T²r)

➙ F = 4π²r / T²

Hence, F ∝ r

⭆ a₁/a₂ = (r₁)/(r₂)

⭆ a₁/a₂ = R/r

a₁ : a₂ = R : r

Cheers!

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