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Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radii R and r such that their
periods are the same. Then the ratio between their centripetal acceleration is:
(A) R/r
(B) r/R
(C) R^2 / r^2
(D) r^2 / R^2
Answers
Answer:
hi there!!
Explanation:
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refer to the picture....as time is constant for both, I am using this formulae.
11th/Physics
Gravitation
Answer :
Two bodies of masses 10kg and 5kg are moving in concentric orbits of radii R and such that their periods are same.
We have to find the ratio between their centripetal acceleration
⧪ First we have to derive relation between centripetal force acting on moving object in circular path and time period of revolution.
★ Centripetal force acting on the body of mass m moving with velocity v in circular path of radius r is given by
- a = v² / r
We know that, v = r × ω = r × (2π/T)
ω denotes angular velocity
T denotes time period of revolution
➙ F = v² / r
➙ F = (2πr/T)² / r
➙ F = (4π²r²) / (T²r)
➙ F = 4π²r / T²
Hence, F ∝ r
⭆ a₁/a₂ = (r₁)/(r₂)
⭆ a₁/a₂ = R/r
⭆ a₁ : a₂ = R : r