Question

help help me me me please ​

Answer 1

Step-by-step explanation:

$\frac{3 - + \sqrt{19} }{5}$

is outcome

given:-

$5 {x}^{2} - 6x - 2 = 0$

asked:-

both value of "x"

∆ analysing the question

we get:-

a= 5

b=-6

c-2

because we can't factories this equation normally so we will use this formula :-

$x = \frac{ - b - + \sqrt{ {b}^{2} - 4ac } }{2a}$

∆ putting those value in the equation:-

$x = \frac{ - ( - 6) - + \sqrt{ ({ - 6)}^{2} - 4 \times 5 \times ( - 2) } }{2 \times 5}$

$x = \frac{6 - + \sqrt{36 + 40} }{10} \\ x = \frac{6 - + \sqrt{76} }{10}$

$x = \frac{6 - + 2 \sqrt{19} }{10} = \frac{3 - + \sqrt{19} }{5}$

this is your answer