Question

help help please....

Answer 1

YOUR ANSWER IS IN THE ATTACHMENT...

HOPE IT HELPS.....

Answer 2

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Solution !

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from LHS

sec¢ + tan¢ = p ________(1)

1/sec¢ + 1/tan¢ = 1/p

multiplying by sec¢ - tan¢ on numerator and denominator .

then , sec¢ - tan¢ / sec²¢ - tan²¢ = 1/p

sec¢ - tan¢ = 1/p ___________(2)

adding both equation .

sec¢ - tan¢ + sec¢ + tan¢ = (1/p + p)

2sec¢ = p² + 1/p ___________(3)

again. substracting 2 from 1

sec¢ + tan¢ -( sec¢ - tan¢) = p - 1/p

2tan¢ = p² - 1/p _______(4)

dividing (4) to (3)

2tan¢ /2sec¢ = p² -1 /p² + 1

sin¢ = p² -1 /p² + 1

Hence , here prooved LHS = RHS

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$\boxed{hope \: it \: helps}$

$\bold \pink{ \star \: muskraj \star }$❤