help i need the answer quickly
its the sixth one
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Let area of the circle be A
therefore area of sector AOB =x/360×A
and it is also given that area of sector =5/18A
so both are equal to each other
=(x/360)A=(5/18)A
therefore x=5/18×360=100°
therefore area of sector AOB =x/360×A
and it is also given that area of sector =5/18A
so both are equal to each other
=(x/360)A=(5/18)A
therefore x=5/18×360=100°
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