Question

help I will give brainlyest easy
2 min I promise plz help​

Answer 1

Step-by-step explanation:

If we find the length of each side

we get a common length of 26 cm

Hence, the given fig. is of a square

Since area of square =

${s}^{2}$

Also, there are two triangle shapes in the fig..

so, we need

area of triangle =

$\frac{1}{2} \times base \times height$

Therefore,

the area of shaded region = area of square ABCD - (area of ∆ AFE + area of ∆ EBG)

=

${s}^{2} - (\frac{1}{2} \times AF \times AE \times ) + ( \frac{1}{2} \times EB \times BG)$

${s}^{2} - (\frac{1}{2} \times AF \times AE \times ) + ( \frac{1}{2} \times EB \times BG) \\ = ({26})^{2} - ( \frac{1}{2} \times 8 \times 16) + ( \frac{1}{2} \times 10 \times 18) \\ = 676 - ( \frac{128}{2}) + ( \frac{180}{2} ) \\ = 676 - 64 + 90 \\ = 676 - 154 \\ = 522 \: {cm}^{2}$

The area of the shaded region is 522 cm².