Math, asked by yahyachoudhury8, 4 days ago

Help! I WILL TRY TO AWARD BRAINLIEST IF IT ALLOWS ME. Any silly answers will be reported. 50 points!

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Answered by BrainlySrijanll
3

B e^(-Ct) acts on a particle whose mass is m and whose velocity is 0 at t= 0 . Its terminal velocity is.

F = B*e^(-C*t)

Here, force is varying with time. So acceleration produced by the force will be;

a = (B/m)*e^(-C*t)

Where m is the mass of the body upon which the force is acting.

Terminal velocity implies the velocity when time tends to infinity.

Since, acceleration is varying, the change in velocity can be obtained by integrating acceleration with respect to time:

v - [initial velocity at (t=0)] = integral (a*dt)

v - 0 = [(-B/m*C)*e^(-C*t)] {from 0 to infinity}

Putting the values of t=0 and t=infinity;

v - 0 = [0 - (-B/m*C)*e^(-C*{t=infinity})]

v = B/m*C

\huge\red{➳Ṧřîⅉꫝᾇñ ࿐}

Answered by AnanyaBaalveer
1

Answer:

v=B/m*c

Step-by-step explanation:

hope helpful

thank you

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