Question

Help!!!!!!


If the quadratic equation
${x}^{2} - 3xk + 2 {e}^{2 log(k) } - 1 = 0$
has real roots such that the product of roots is 7, then the value of k is :

(1) +/- 1
(2) +/- 2
(3) +/- 3
(4) None of these.


Note: Need well explained answer.

Answer 1

Hey friend, Harish here.

Here is your answer. (Refer to the image).

Solve it we get k = ± 2

But log of negative number is not defined.

So the only correct answer will be be k = 2

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Hope my answer is helpful to you.

Answer 2

hope this helps you.