Question

help in solving question 1,2(b,c)

Answer 1

1) for value of polynomial at some point,put that point in the polynomial
p(0)=5
p(1)=1-3+5=3
p(-2)=-8+6+5=3
2)b)

$3au - 4 {a}^{2} = 0 \\ a(3u - 4a) = 0$
$3u = 4a \\ u = \frac{4a}{3}$
c)
$3\pi \: x - 4 = 0 \\ 3\pi \: x = 4 \\ x = \frac{4}{3\pi}$