Question

help in this qn...........

Answer 1

q= EA/d) V

when dielectric is inserted

capacitance = 2EA/d × 4EA/d)/6EA/d = 4EA/3d
( as they are in series that is dielectric of d/2 thickness and without dielectric)

q remains same

q = 4EA/3d. V1

V1 = 3V/4