Question

help in this question​

Answer 1

Here

/_ 1=/_2,,,so PQ will equal to PR

hence

$\frac{qr}{qs} = \frac{qt}{qp}$

Now in triangle PQS and TQR,

QR/QS=QT/QP

and /_1 in common

Hence,PQS is similar to TQR