Question

help in this question
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Answer 1

$\Large\mathfrak \purple {\bigstar ~~Question:-}$

In ∆ABC, AC=BC, then value of x is ?

$\Large \mathfrak \purple {\bigstar ~~Solution:-}$

Since AC = BC, <CAB = <CBA

[Angles opposite to equal sides are equal]

So, (4x+5) = (5x-5)

$\blue \leadsto \sf 4x + 5 = 5 x- 5$

$\blue \leadsto \sf 4x -5x=-5-5$

$\blue \leadsto \sf -x=-10$

$\blue \leadsto \sf x=10$

▪️Therefore, x = 10 for the angles.

$\Large \mathfrak \purple {\bigstar~~Verification:-}$

Substituting x = 10 in (4x+5) and (5x-5) :-

$\blue \leadsto \sf 4(10)+5=5(10)-5$

$\blue \leadsto \sf 40+5=50-5$

$\blue \leadsto \sf 45=45$

▪️ LHS = RHS

▪️ Henceforth, verified !

Therefore, x = 10 for (4x+5) and (5x-5) when AC = BC in ∆ABC.

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