Question

help in this question please ​

Answer 1

Answer:

Force of Friction will be mgCos 30°

Force = 0.01 * 10 * √3/2

Force = 0.05√3 N

Now Weight of Second Block = 0.05√3 N

= 0.05√3 / 10

= 0.005√3

= 5√3g

Weight of Second Block should be 5√3g.

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Answer 2

Answer:

5g

Explanation:

Force in downword direction of mass M is MgsinФ......which is equal to 10g(1/2)= 5g

tension must be 5g to be in equllibirium

so,

T= mg

5g = mg

m=5

m = 5 gram

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