Math, asked by ishaziz2002, 1 year ago

help in this question
sec50° sin40°+cos40°cosec60°

Answers

Answered by sudip20
1
sec50sin40+cos40cosec60
=sec(90-40)sin40+cos(90-60)cosec60
=cosec40xsin40 + sin60 x cosec60

  = \frac{1}{ \sin(40) }  \times  \sin(40)  +  \frac{1}{ \ \csc (60) }  \times  \csc(60)
=1+1
=2
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