Question

help it is math simpfyin

Answer 1

Answer:

3/2

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Step-by-step explanation:

$6\frac{1}{2} - [\frac{2}{3} of 1\frac{1}{2} + (6 / 1\frac{1}{2} )]$

First, we convert all the mixed fractions into improper fractions.

$= \frac{13}{2} - [\frac{2}{3} * \frac{3}{2} + (6 / \frac{3}{2} )]$

According to BODMAS (Brackets, Division, Multiplication, Addition, Subtraction), we first solve the round brackets.

$= \frac{13}{2} - [\frac{2}{3} * \frac{3}{2} + (6 * \frac{2}{3} )]$

$= \frac{13}{2} - [\frac{2}{3} * \frac{3}{2} + (2 * \frac{2}{1} )]$

$= \frac{13}{2} - [\frac{2}{3} * \frac{3}{2} + 4]$

Then, we solve the curly brackets (In this case, I was not able to add the flower brackets, hence, I have used square brackets.)

Inside the brackets, we have 2 operations: multiplication and addition. According to BODMAS, we will first multiply.

The product of a rational number and it's reciprocal is always 1.

$= \frac{13}{2} - [1 + 4]$

Next, we add 1 and 4 (it is the last operation to be done inside brackets.

$= \frac{13}{2} - 5$

Now that we only have one operation left, we can continue solving as we normally would.

$\frac{13}{2} - 5\\= \frac{13}{2} - \frac{5*2}{2} \\= \frac{13}{2} - \frac{10}{2}\\= \frac{13 - 10}{2} = \frac{3}{2}$