Physics, asked by Jalalalalala, 11 months ago

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Answered by 14riyaz14

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$\huge\underline\green{\mathcal Answer}$

$\large{\mathcal Tangential\: acceleration (at)={\frac{dv}{dt}}}$

$\large{\boxed{\mathcal at=4t}}$

$\large{\mathcal Centripetal\: Acceleration (ac)={\frac{{v}^{2}}{r}}}$

$\large{\boxed{\mathcal ac={\frac{{v}^{2}}{r}}}}$

$\large{\mathcal ac={4t}^{2}}$

$\large{\mathcal Net\: Acceleration={\sqrt{{at}^{2}+{ac}^{2}}}}$

$\large{\boxed{\mathcal Net\: Acceleration=4{\sqrt{2}}}}$

Answered by ItzShubhi

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