Math, asked by Karamkandi22, 12 days ago

help karo na...
pleaj...
°‿°

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Answers

Answered by deepuchauhan628

0

Step-by-step explanation:

cot15

∘

.cot20

∘

.cot70

∘

.cot75

∘

is

=(cot15

∘

.cot75

∘

)(cot20

∘

cot70

∘

)

Now cot75

∘

=tan15

∘

and cot70

∘

=tan20

∘

cot(90−θ)=tanθ

Therefore, the given expression can be written as

(cot15

∘

tan15

∘

)(cot20

∘

tan20

Answered by xxbrainlyqueenxx26

1

ahmm ahmm

tu karry hai?.....

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