help mate....who can solve it
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a=3**3-2**3
a=27-8
a=19
a=5**3-4**3
a=125-64
a=61
a=7**3-6**3
a=343-216
a=127
hence the a .p come out to be
19 , 61. , 127...….....
hence the first term is 19
second term 61
third term127
A=61-19
=42
A=127-61
=66
hence if 24 more number is added to each.
42, 66...
so sum up to n terms is
sum of n terms=n/2(2*42+(n-1)24)
=n/2(84+24n-24)
=n(30+12n)
=12n**2+30 is the sum of n terms.
so sum up to ten terms
sum of ten terms=10/2(2*42+(9)*24)
=10/2(84+216)
=10/2(300)
=3000/2
=1500
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