Math, asked by hellos74, 1 year ago

Help me!!!!!!!!!!!!!!!!!!!!!!! ​

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Answered by Anonymous
15

SOLUTION

  =  &gt; f(x) = 3 {x}^{2}  - 6x + 8 \\  =  &gt; </u><u>f'</u><u>(x) = 3.2x - 6 + 0  = 0\\  =  &gt; </u><u>f'</u><u>(x) = 6x = 6 \\ =  &gt; </u><u>f'</u><u>(x) = x = 1 \\   \\  =  &gt; </u><u>f</u><u>"</u><u>(x) = 6 &lt; 0....max. \\  =  &gt; f(1) = 3( {1})^{2}  - 6(1) + 8 \\  =  &gt; 3 - 6 + 8   \\  =  &gt;  - 3 + 8  \\  =  &gt; 5

Maximum value is 5.

hope it helps ☺️

Answered by Anonymous
0

Answer:

PLEASE REFER TO THE ATTACHMENT!!

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