Question

Help me!!!!!!!!!!!!!!!!!!!!!!! ​

Answer 1

SOLUTION

$= > f(x) = 3 {x}^{2} - 6x + 8 \\ = > </u><u>f'</u><u>(x) = 3.2x - 6 + 0 = 0\\ = > </u><u>f'</u><u>(x) = 6x = 6 \\ = > </u><u>f'</u><u>(x) = x = 1 \\ \\ = > </u><u>f</u><u>"</u><u>(x) = 6 < 0....max. \\ = > f(1) = 3( {1})^{2} - 6(1) + 8 \\ = > 3 - 6 + 8 \\ = > - 3 + 8 \\ = > 5$

Maximum value is 5.

hope it helps ☺️

Answer 2

Answer:

PLEASE REFER TO THE ATTACHMENT!!