Question

help me ..............​

Answer 1

Step-by-step explanation:

Some of all three angles pf triangles=180°

So, In ∆AOC, 20°+100°+OAC=180°

So, OAC=60°

Similarly, In ∆BOD

OBD=100°

SO, In ∆AOC & In ∆B0D

OAC=ODB=6O°

&AC=DB=4 cm

& OCA=OBD=100°

So, ∆AOC is congruent to ∆DOB

(by ASA criteria)

!HENCE PROVED!

May this help you

Answer 2

Angle AOC = DOB (60 degrees) ANGLE
AC = DB (4 cm ) SIDE
Angle ACO = DBO (100 degrees) ANGLE
AOC is congruent to DOB