Question

Help me!!!!!!!!


3x + 2y - (k-4) = 0

6x + 4y - 8 = 0


Q.1)write the condition for infinitely many solution.

Q.2)Find the value of k.


‼️SEE IN THE PHOTO‼️

Answer 1

condition for infinitely many solutions is a1/a2=b1/b2=c1/c2

here a1=3,b1=2,c1=-(k-4),a2=6,b2=4,c2=-8..hence

a1/a2=b1/b2=c1/c2

3/6=2/4=-(k-4)/-8

k-4/8=1/2

k-4/4=1

k-4=4

k=4+4

k=8