Question

help me.....
(a+b)(c-d) + (a-b)(c+d) + 2(ac+bd)

Answer 1

HEYA MATE!!!

HERE IS THE SOLUTION..

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(a+b)(c-d) + (a-b)(c+d) + 2(ac+bd)

= ac - ad + bc - bd + ac + ad - bc - bd + 2ac + 2bd

= ac + ac + 2ac - bd - bd - 2bd

= 4ac - 2bd + 2bd

= 4ac


HOPE IT HELPS U㊗㊙

Answer 2

Hii...

(a+b)+(c-d)+(a-b)(c+d)+2(ac+bd)

ac-cd+ac-bc+2ac+2bd

=====4ac-cd-bc+2bd