help me alia pl_zzzzzzzz
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let the fraction be x/y
now, ATQ. 2(x) = y+2
2x -2 = y ➡1⃣
x+3
—— = 2/3
y+3
3(x+3) = 2(y+3)
3x + 9 = 2y + 6
3x -2y = -3 ➡2⃣
From eq. 1 and 2
3x -2(2x-2) = -3
3x -4x +4 = -3
-x +4 = -3
4+3 = x
[x = 7]
so by substituting value of x in eq.1
2(7)-2 = y
14-2= y
[y = 12]
•°• 7/12 is the fraction
Hope this helps u......✌✌
now, ATQ. 2(x) = y+2
2x -2 = y ➡1⃣
x+3
—— = 2/3
y+3
3(x+3) = 2(y+3)
3x + 9 = 2y + 6
3x -2y = -3 ➡2⃣
From eq. 1 and 2
3x -2(2x-2) = -3
3x -4x +4 = -3
-x +4 = -3
4+3 = x
[x = 7]
so by substituting value of x in eq.1
2(7)-2 = y
14-2= y
[y = 12]
•°• 7/12 is the fraction
Hope this helps u......✌✌
jass9584:
is answer right???
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