Question

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Each of the two equal angles of a triangle is twice to he third angle. Find the angles of the triangle.​

Answer 1

Answer:

In triangle

∠ABC = ∠ACB = x

and

∠BAC = 2 ∠ABC = 2∠ACB = 2x

∴ Sum of all the angles of triangle =180°

∴ x + x + 2x = 180°

∴ 4x = 180°

∴ x = 45°

∴ ∠ABC = ∠ACB = x = 45°

∴ ∠BAC = 2x = 90°

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