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sec^2 x - tan^2 x=1
1+tan^2 x= sec^2 x
(1+tan^2 x)cot x/cosec^2 x
sec^2x/cosec^2 x=tan^2 x
tan x.tan x cot x
=tan x
1+tan^2 x= sec^2 x
(1+tan^2 x)cot x/cosec^2 x
sec^2x/cosec^2 x=tan^2 x
tan x.tan x cot x
=tan x
Answered by
3
Hey ,
1+tan²Q = Sec²Q
.
so ,( Sec²Q×CotQ )\Cosec²Q
.
Here , H = hypotenuse
P = perpendicular
B = Base
.
[(H\B)²×B\P]\(H\P)²
(H²\B.P)\H²\P²
P\B
.
That is TanQ .
Hence Proved
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1+tan²Q = Sec²Q
.
so ,( Sec²Q×CotQ )\Cosec²Q
.
Here , H = hypotenuse
P = perpendicular
B = Base
.
[(H\B)²×B\P]\(H\P)²
(H²\B.P)\H²\P²
P\B
.
That is TanQ .
Hence Proved
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