Math, asked by aAna0636l49, 10 months ago

help me by giving answer plz plz plz



Question no=7​

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Answered by wxyza
0

Answer

zero of polynomial x+2=0

                                x= -2

p(x)=(x+1)^7 + (2x+k)^3

p(-2)=(-2+1)^7 + (2*-2+k)3

         (-1)^7 + (-4+k)^3

          -1 - 64 + k^3 - 12k (-4 + k)

          -65+K^3+48k-12(k)^2=0      (x+2 is factor of p(x) ,so remainder = 0)

           k^3 + 48k-12(k)^2=65

            k(k^2+48-12k)=65

             


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