Question

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Answer 1

Answer:

In ∆ABC,

M is the midpoint of segBC

•By Apollonius Theorem,we get,

AB^2+AC^2=2AM^2+2BM^2

290=2(8)^2+2BM^2..........(given)

290=2(64)+2BM^2

290=128+2BM^2

290-128=2BM^2

162=2BM^2

162/2=BM^2

81=BM^2

√81=BM

BM=9 units

Now,

It is given that M ist the midpoint of segBC

•BM=MC

•BM=MC=9 units

Now,

BC=BM+MC..........(since B-M-C(

BC=9+9

BC=18 units

Therefore, the length of segment BC is 18 units.