Question

help me chemistry class 11

Answer 1

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please refer to the attachment above





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Answer 2

$\underline{\bold{Given:-}}$

$P_{1} = 1 \: bar \: \: \: \: \: \: \: \: \: \: \: \: V_{1} = \: 2.24 \: lit \\ \\ P_{2} = \: 0.2 \: bar \: \: \: \: \: \: \: V_{2} =?$

$\underline{\bold{Solution:-}}$

Boyle's law will be used in solving the question.

So, using Boyle's law

$P_{1} \: V_{1} = P_{2} \: V_{2} \\ \\ V_{2} = \frac{ P_{1} \: V_{1}}{ P_{2} } \\ \\ V_{2} = \frac{1 \times 2.27}{0.2}$

$V_{2} = 11.35 \: lit$

Since, the balloon brust if the pressure exceed 0. 2 bar.

So, the balloon can expand up to the volume 11. 35 litres.