Question

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(d) 3 cos 80°. cosec 10° + 2 cos 59º. cosec 31°

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Answer 1

Answer:

3 cos 80× cosec 10 +2 cos 59 × cosec 31 = 3 cos 80 ÷ sin 10 + 2 cos 59 ÷ sin 31 =

3 cos 80÷ sin (90 - 80 ) + 2 cos 59 ÷ sin (90 - 59) = 3 × cos 80 ÷ cos 80 + 2 cos 51 ÷ cos 51 = 3 +2 =5