Question

help me do this question!!​

Answer 1

√3 x^2-2√2 x-2√3=0

it is in the form of ax^2+bx+c=0

a=√3,b=-2√2,c=-2√3

X= -b+_√b^2-4ac

2a

X=-(-2√3)+_√(-2√3)^2-4(√3)(-2√3)

2√3

X=2√3+_√12+24

2√3

X=2√3+_√36

2√3

X=2√3+_6

2√3

X=2√3+6. X=2√3-6

2√3. 2√3

X=2(√3+3) X=2(√3-3)

2√3. 2√3

X=√3(1+√3). X=√3(1-√3)

√3. √3

X=1+√3. X=1-√3

mark me as brainliest please

Answer 2

$\large \mathfrak \red{Answer:-}$

$\tt{x = \frac{ - \sqrt{6} }{3} \: \: or \: \: \sqrt{6} }$