Question

help me do this question from matrices​

Answer 1

by question

$(x - 2)2x - ( - 3)3x = 3 \\ 2 {x}^{2} - 4x + 9x = 3 \\ 2 {x}^{2} + 5x - 3 = 0 \\ 2 {x}^{2} + 6x - x - 3 = 0 \\ 2x(x + 3) - 1(x + 3) = 0 \\ (2x - 1)(x + 3) = 0$

$Therefore \: x = \frac{1}{2} \: or \: ( - 3)$

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