Question

help me explain steps ​

Answer 1

Answer:

Step-by-step explanation:

From the properties of of logarithms we know,

  loga + logb + logc = log( a*b*c )

The same, applying here:

$\implies\mathrm{log\dfrac{a^2}{bc} +log\dfrac{b^2}{ac}+log\dfrac{c^2}{ab}}\\\\\\\implies\mathrm{ log\bigg(\dfrac{a^2}{bc} \times\dfrac{ b^2}{ac}\times\dfrac{c^2}{ab}\bigg)}\\\\\\\implies\mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{ ab \times bc \times ac} \bigg)}\\\\\\\implies \mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{a^2 \times b^2 \times c^2} \bigg)}$

⇒ log 1

⇒ 0      { log 1 = 0 }

 Hence proved.