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put the vlaue of b in sin nd cos
now Sin2×30=Sin60 degree then put the vlaue of Sin 60 is √3/2
now you solve the 2SinB×CosB put B=30 then 2×1/2×√3/2=√3/2 now you solve the rhs portion as well
Then after solving u find that
LHS=RHS......
I hope you understand it....
please mark it as a brainieist answer.......
now Sin2×30=Sin60 degree then put the vlaue of Sin 60 is √3/2
now you solve the 2SinB×CosB put B=30 then 2×1/2×√3/2=√3/2 now you solve the rhs portion as well
Then after solving u find that
LHS=RHS......
I hope you understand it....
please mark it as a brainieist answer.......
Aasthakatheriya1:
oh i am sorry i do mistake in last line in place of 2 i write 4
no i understand it
i hope u understand it now
no that's write but it should be root 3/2
whole root as u telll
ok leave
in last line you should applied a/b/c/d = a×d/b×c
yaa
and thank u
ur welcome
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