help me finding this question. with explanation.......... some applications of trigonometry
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safiasaheb:
it is more based on the concept of similarity....
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consider ΔPQC and ΔABC
∠PQC=∠ABC=90°
∠PCQ=∠ACB (COMMON ANGLE)
∴ΔPQC ≈ ΔABC
∴PQ/QC=AB/BC (BPT)
1.6/4.8=AB/8
MULTIPLY WITH 10 ON LHS
16/48=AB/8
16×8/48=AB
AB=2.6CM
∴HEIGHT OF THE TOWER IS 2.6CM
∠PQC=∠ABC=90°
∠PCQ=∠ACB (COMMON ANGLE)
∴ΔPQC ≈ ΔABC
∴PQ/QC=AB/BC (BPT)
1.6/4.8=AB/8
MULTIPLY WITH 10 ON LHS
16/48=AB/8
16×8/48=AB
AB=2.6CM
∴HEIGHT OF THE TOWER IS 2.6CM
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