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Given that 3/7 + (- 6/11) + (- 8/21) + (5/22)
Taking L.C.M. of the denominators 7, 11, 21 and 22 and then solving it.
L.C.M. of 7, 11, 21 and 22 = 2 x 3 x 7 x 11 = 462
= (462/7) x 3 – (462/11) x 6 – (462/21) x 8 + (462/22) x 5
= (198/462) – (252/462) – (176/462) + (105/462)
= (303/462) – (428/462)
= (-125/462)
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