Question

help me...friends
pls

Answer 1

hope it helps you mate

Answer 2

Heya!!

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Since a^x = b,
b^y = c
& c^z = a.

Since b^y = c

=) (a^x) ^y = c

=) a^(xy) = c

By third given;

=) c^z = a

=) [a^(xy)] ^z = a

=) a^(xyz) = a

=) a^(xyz) = a^1

=) xyz = 1

Hope it helps uh :)